Page 111 - Maths Class 06

SOLUTION : In Fig. (a) 1 part is shaded out of 2 parts,
1
Therefore, it represents .
2
4 2 3 1
(b) represents = (c) represents =
6 3 9 3
2 1 3
(d) represents = (e) represents
8 4 4
In Fig. (i) 6 parts are shaded out of 18 parts,
6 1
Therefore, it represents =
18 3
4 1 12 3
(ii) represents = = (iii) represents =
8 2 16 4
8 2 4 1
(iv) represents = = (v) represents =
12 3 16 4
Thus, the pairs of equivalent fractions are (a)-(ii); (b)-(iv); (c)-(i); (d)-(v); (e)-(iii)
1 1
EX AM PLE 3. Add and .
6 7
SOLUTION : The given frac tions are un like.

LCM of 6 and 7 is 42.
1 7 1 6
= , =
6 42 7 42
1 1 7 6 13
Thus, + = + =
6 7 42 42 42
2 5
EX AM PLE 4. Find 6 - 1 .
3 7

SO LU TION : Expressing the mixed frac tions as im proper frac tion, we have
2 20 5 12
6 = , 1 =
3 3 7 7
20 12 (20 ´ )7 -(12 ´ )3
- =
3 7 21
140 -36 104 20
= = = 4
21 21 21

1 1
EX AM PLE 5. A juice shop owner con sumes 20 kg of or anges in the morn ing and 24 kg in the eve ning.
2 3
Find the to tal con sump tion of or anges in a day.
1
SO LU TION : Oranges con sumed in morn ing = 20 kg
2
1
Oranges consumed in evening = 24 kg
3
1 1
Total oranges consumed = 20 + 24
2 3
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